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I think this is because "now" is the current time, while "tomorrow" is the current day +1 but at a default time, lets say: Now: pm, Tomorrow: am, In this case, the difference is not 24 hour, so it will says 0 days.Better use "today", which should also use a default value like: Today: am, Tomorrow: am, which now is 24 hour and represents 1 day.

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Therefore I hope this can help some others: When calculating with the date() function it was more accurate (didn't use seconds/hours for comparison).

Note that 3 days may be a lot if you want to create invoices and have to check against a given age to determine if the customer is chargable for taxes and so on.

If someone also found this behaviour I'd like to hear about it - give me a quick mail at schindhelm (at) gmail (dot) com. When using datediff make sure your time zone is correct, for me on Windows 7 64 bit it behaved very strange when timezone was wrong (I was comparing now against time in database and exif metadata in photos). This will output the number of days,months, or years difference between NOW and a April 1st, 2011.

For example: date_default_timezone_set('Europe/Oslo'); I was looking for a way to output X number of days from a given date and didn't find exactly what I was looking for. For those like me who don't yet have PHP 5.3 installed on their host, here's a simple alternative to get the number of days between two dates in the format '2010-3-23' or similar acceptable to strtotime(). Similar to what was mentioned by ianlenmac at gmail dot com I think its also worth mentioning to note that date_diff($datetime1, $datetime2) is equivalent to " subtract $datetime1 from $datetime2 " as opposed to thinking otherwise because of the arrangement of the arguments so date_diff($now, $tomorrow) is +veformat('In %a days'); In some situations, this won't say "in 1 days", but "in 0 days".

Here you have in this post code to get the age of a person specifying the date of birth:function get Age($birthdate){ $adjust = (date("md") = date("md", strtotime($birthdate))) ?

Submit a bug or feature For further API reference and developer documentation, see Java SE Documentation. That documentation contains more detailed, developer-targeted descriptions, with conceptual overviews, definitions of terms, workarounds, and working code examples. After wrestling with Date Time::diff for a while it finally dawned on me the problem was both in the formatting of the input string and the formatting of the output. Both of these strings are valid: If you want to quickly scan through the resulting intervals, you can use the undocumented properties of Date Interval.The task was to calculate the duration between two date/times. The function below returns a single number of years, months, days, hours, minutes or seconds between the current date and the provided date.If the date occurs in the past (is negative/inverted), it suffixes it with 'ago'.Though I found a number of people who ran into the issue of 5.2 and lower not supporting this function, I was unable to find any solid examples to get around it.

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